If the point (2,a) lies on the line 2x-y=3 then 'a' is equal to

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Solution

The correct option is C
1

Given:
Equation of straight line 2x-y=3 passes through the point (2,a)
Substituting x=2 and y=a in the given equation we get:
$\Rightarrow 2 \times 2 - (a) = 3 \Rightarrow 4 - a = 3 \Rightarrow 4 - 3 = a \Rightarrow a = 1$

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Similar questions

Q. If the point (2, a ) lies on the line 2x + y = 5, then the value of a is ______

Q. If the point (2, -3) lies on

k x^{2} - 3 y^{2} + 2 x + y - 2 = 0

then k is equal to

State, true or false :

(i) the line $\frac{x}{2} + \frac{y}{3} = 0$ passes through the point (2, 3).

(ii) the line $\frac{x}{2} + \frac{y}{3} = 0$ passes through the point (4, -6).

(iii) the point (8, 7) lies on the line y - 7 = 0

(iv) the point (-3, 0) lies on the line x + 3 = 0

(v) if the point (2, a) lies on the line 2x - y = 3, then a = 5.

P

is a point on the circle

C_{1} : q^{2} (x^{2} + y^{2}) = a^{2} p^{2}

Q

is a point on the circle

C_{2} : x^{2} + y^{2} = a^{2}

If the point

(p, q)

lies on the line

y = 2 x,

then

\frac{r a d i u s o f C_{3}}{r a d i u s o f C_{2}}

equal to :

Solve:
(a) Find the point on y = 2x + 2 where the ordinate is thrice the abscissa
(b) If the point P lies on the line x = 5 and has its ordinate equal to –3, then find its coordinates. [3 MARKS]

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If the point (2,a) lies on the line 2x-y=3 then 'a' is equal to

The correct option is C 1 Given: Equation of straight line 2x-y=3 passes through the point (2,a) Substituting x=2 and y=a in the given equation we get: ⇒2×2−(a)=3⇒4−a=3⇒4−3=a⇒a=1

The correct option is C
1

Given:
Equation of straight line 2x-y=3 passes through the point (2,a)
Substituting x=2 and y=a in the given equation we get:
$\Rightarrow 2 \times 2 - (a) = 3 \Rightarrow 4 - a = 3 \Rightarrow 4 - 3 = a \Rightarrow a = 1$