Question

If the point $(3,4)$ lies on the equation $3y=ax+7$, then the value of $a$ is

• A. $\frac{3}{5}$
• B. $-\frac{3}{5}$
• C. $-\frac{5}{3}$
• D. $\frac{5}{3}$

Answer 1

Answer: (D)

$\frac{5}{3}$

Since,the point $(3,4)$ lies on the graph of the equation $3y=ax+7$,
The point satisfies the equation.
So, we put $x=3,y=4$ in given equation,
$3\left(4\right)=a\left(3\right)+7$
$12=3a+7$
$3a=12-7$
$3a=5$
$\Rightarrow a=\frac{5}{3}$