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Standard XII

Mathematics

Location of Roots

If the point ...

Question

If the point $(a, 2)$ lies between the lines $x - y - 1 = 0$ and $2 (x - y) - 5 = 0$ , then the set of values of $a$ is -

(- \infty, 3) \cup (\frac{9}{2}, \infty)

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(3, \frac{9}{2})

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(- \infty, 3)

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(\frac{9}{2}, \infty)

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Solution

The correct option is B $(3, \frac{9}{2})$
$x - y = 1$ and $x - y = \frac{5}{2}$
if point $(a, 2)$ lies between these two lines.
then
$1 < (a - 2) < \frac{5}{2}$
$\Rightarrow 3 < a < \frac{9}{2}$
$∴ B$

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If the point (a,2) lies between the lines x−y−1=0 and 2(x−y)−5=0, then the set of values of a is -

The correct option is B (3,92)x−y=1 and x−y=52if point (a,2) lies between these two lines.then 1<(a−2)<52⇒3<a<92∴B

If the point $(a, 2)$ lies between the lines $x - y - 1 = 0$ and $2 (x - y) - 5 = 0$ , then the set of values of $a$ is -

The correct option is B $(3, \frac{9}{2})$
$x - y = 1$ and $x - y = \frac{5}{2}$
if point $(a, 2)$ lies between these two lines.
then
$1 < (a - 2) < \frac{5}{2}$
$\Rightarrow 3 < a < \frac{9}{2}$
$∴ B$