If the point (a,a+1) belongs to the interior of the region bounded curve y=√5−x2 and the x-axis then a belongs to
A
(−2,1)
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B
(−1,1)
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C
(−2,0)
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D
(0,1)
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Solution
The correct option is A(−2,1) Given curve is clearly a circle, x2+y2=5 For (a,a+1) to be interior point of the given curve, a2+(a+1)2<5 ⇒2a2+2a−4<0 ⇒a2+a−2<⇒(a−1)(a+2)<0 ⇒aϵ(−2,1)