Ratio given (2:3) = (m:n) A(2,6)=(x1,y1)
B(5,1)=(x2,y2)
C(k,4)=(x,y)
By section formula,we get 2×5+3×22+3=k [1 Mark]
10+65=k
16=5k k=165 [1 Mark]
If the point C(k,4) divides the join of A(2, 6) and B(5, 1) in the ratio 2:3 then find the value of k. [2 Marks]