If the point $(k - 1, k + 3)$ lies on the line $3 x + 2 y + 7 = 0$ , find the value of $k$ .
2

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Solution

The correct option is A 2
Since the point $(k - 1, k + 3)$ lies on the line $3 x + 2 y + 7 = 0$ ,

$3 (k - 1) + 2 (k + 3) + 7 = 0$

$\Rightarrow 3 k - 3 + 2 k + 6 + 7 = 0$

$\Rightarrow 5 k = 10 \Rightarrow k = \frac{10}{5} = 2$ .

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