Question

If the point $(3,4)$ lies on the graph of the equation $3y=ax+7$, find the value of $a$.

Answer 1

Given line is $3y=ax+7$

Since, the point $(3,4)$ lies on the line $3y=ax+7$.

i.e., $x=3$ and $y=4$ satisfies the equation.

$\Rightarrow 3y=ax+7$

$\Rightarrow 3\times 4=a\times 3+7$

$\Rightarrow 12=3a+7$

$\Rightarrow 3a=12-7$

$\Rightarrow 3a=5$

$\Rightarrow a=\frac{5}{3}$

$\Rightarrow a=1\frac{2}{3}$

Therefore, the value of $a$ is $1\frac{2}{3}$.