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Question

# If the point of intersection of the lines x + 2y - 3 = 0 and x - 4y - 9 = 0 is 5 units away from the center of the circle having coordinates (x, 4), the value of x is -

A

1

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B

2

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C

3

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D

4

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E

5

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Solution

## The correct option is E 5 The point of intersection of the lines x + 2y - 3 = 0 and x - 4y - 9 = 0 is (5,-1). The point which is at a distance of 5 units from the point (5, -1) is (x, 4). Distance formula = √(x2−x1)2+(y2−y1)2 Solving we get x = 5.

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