If the point P(5, k-2) lies on the line x−2y+1=0, then find the value of k.
5
6
4
3
If P(5, k-2) lies on the line x−2y+1=0,
then its coordinates must satisfy the equation of the line.
Thus,
5−2(k−2)+1=0
5−2k+4+1=0
2k=10
k=5
If the point (2k – 3, k + 2) lies on the line 2x + 3y + 15 = 0, find the value of k.
If the point P(a,5) lies on the line 2x−3y−5=0, then find the value of a.