If the point P(a, 2) is equidistant from the points A(8, -2) and B(2, -2), then a = ___

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Solution

The correct option is B
5

P(a, 2) is equidistant from A(8, -2) and B(2, -2)

Hence, PA = PB

$P A^{2} = P B^{2}$

$(a - 8)^{2} + (2 - (- 2))^{2} = (a - 2)^{2} + (2 - (- 2))^{2}$

$(a - 8)^{2} + / 4^{2} = (a - 2)^{2} + / 4^{2}$

$/ a^{2} - 16 a + 64 = / a^{2} - 4 a + 4$

$12 a = 60$

$a = 5$

Hence (B)

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