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Question

If the points (0,1,2),(3, λ,1) and (μ, 7,4) are collinear, the point on the same line is

A
(5,6,3)
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B
(1,1,2)
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C
(5,6,3)
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D
(0,0,0)
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Solution

The correct option is C (5,6,3)
The direction vector using the first two points we get 3i+(λ1)j+3k.
Using the first and third point μi+6j+6k.
Since they are up to multiplication by a constant we get λ=4 and μ=6.
Hence direction vector is i+j+k.
Any point on the line is given by (0,1,2)+t(1,1,1). Plugging t=5 we get the point (5,6,3).


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