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Question

If the points (1,2) and (3,4) lie on the same side of the straight line 3x−5y+a=0 then a lies in the set

A
[7,11]
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B
R[7,11]
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C
[7,)
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D
(,11]
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Solution

The correct option is D R[7,11]
Since (1,2) and (3,4) lie on the same side of the line,
3(1)5(2)+a and 3(3)5(4)+a must have the same sign.
Hence (310+a)(920+a)>0
or (a7)(a11)>0
For a in [7,11] the above expression becomes negative.
Hence a lies in the set R[7,11].

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