wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If the points (-2,3), (x, y) and (-3,5) lie on a straight line then the equation of the line is______

A
x2y1=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
2x+y1=0
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
x+2y1=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
2x+y+1=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
E
Answer Required
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 2x+y1=0
Let the line be y=mx+c
The line passes through 3 points (2,3),(x,y)and (3,5)
Now,
3=2×m+c .................. (i)
5=3×m+c .................... (ii)
Subtracting equation (ii) from (i) we get,
m=2
Substitute the value of m in (I) we get,
3=2(2)+c
=>c=43
=>c=1
the equation of the line is
y=mx+c
=>y=2x+1
=>2x+y1=0


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Family of Straight Lines
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon