Question

If the points A(2,3), B(4,k) and C(6,-3) are collinear points, then k = .

• A. 0
• B. 1
• C. 2

Answer 1

The correct option is A 0

Given the points are collinear.
$\therefore$ The area formed by the these points must be zero.
$\frac{1}{2}\left(2\left(k+3\right)+4(-3-3)+6(3-k)\right]$ = 0
i.e.,$\frac{1}{2}(-4k)=0\Rightarrow k=0$