If the points A(2,3), B(4,k) and C(6,-3) are collinear points, then k = .
A
0.0
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B
1
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C
2
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Solution
The correct option is A 0.0 Given the points are collinear. ∴ The area formed by the these points must be zero. 12(2(k+3)+4(−3−3)+6(3−k)] = 0 i.e.,12(−4k)=0⇒k=0