If the points A(7,-2), B(5,1) and C(3,k) are collinear, then the value of K is:

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Solution

The correct option is C
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K

\begin{matrix} A (7, - 2) \end{matrix} \begin{matrix} B (5, 1) \end{matrix} \begin{matrix} C (3, K) \end{matrix}

(\frac{2}{5}, \frac{1}{3}), (\frac{1}{2}, k)

(\frac{4}{5}, 0)

If the point P(5, k-2) lies on the line $x - 2 y + 1 = 0$ , then find the value of k.

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If the points $2^i + 4^J, 7^i + x^j, -^i +^J$ are collinear, then the value of x is

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