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Question

If the points (1,2) and (3,4) were to be on the opposite side of the line 3x5y+a=0, then

A
7<a<11
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B
a=7
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C
a=11
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D
a<7ora>11
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Solution

The correct option is B 7<a<11
If the two points are (1,2) & (3,4) are opposite to line 3x5y+a=0 then,
(3×(1)5×(2)+a)(3×35×4+a)<0
(a7)(a11)<0
7<a<11
Hence, option 'A' is correct.

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