If the points k- 2 k-3 k- 3 k and 3-1 are collinear- then ka 13b -13c 23d -23

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Area of a Triangle Given Its Vertices

If the points...

Question

If the points (k, 2k), (3k, 3k) and (3, 1) are collinear, then k

(a) $\frac{1}{3}$

(b) $- \frac{1}{3}$

(c) $\frac{2}{3}$

(d) $- \frac{2}{3}$

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Similar questions

\frac{1}{3}

\frac{- 1}{3}

\frac{2}{3}

\frac{- 2}{3}

(k, 2 k), (2 k, 3 k), (3, 1)

k

If the sum of the zeros of the quadratic polynomial $k x^{2} + 2 x + 3 k$ is equal to the product of its zeros, then $k =$

$(a) - \frac{1}{3}$
$(b) \frac{1}{3}$
$(c) \frac{2}{3}$
$(d) - \frac{2}{3}$

l

(k, 2 k), (3 k, 3 k)

(3, 1)

k \neq 0

l

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