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Question

If the polynomials ax3+4x2+3x4 and x34x+a leave the same remainder when divided by (x - 3), find the value of a.


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Solution

Let p(x)=ax3+4x2+3x4 and q(x)=x34x+a be the given polynomials. The remainders when p(x) and q(x) are divided by (x - 3) are p(3) and q(3) respectively.

By the given condition, we have
p(3) = q(3)
a×33+4×32+3×34=334×3+a
27a+36+94=2712+a
26a+26=0
26a=26
a=1


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