Question

If the population density of wild animals in Russia is 1, then what is the combined population density of (Africa and North & South America)?

• A. 0.79
• B. 0.84
• C. 0.88
• D. 0.94

Answer 1

The correct option is C 0.88

Pie charts given in the question present two different data for seven regions namely A1 to A7. Left hand piechart presents the population distribution of wild animals in seven regions whereas right hand pie chart presents the land under forest cover distribution in seven regions.
Population density = $\frac{PercentageNumberofAnimals}{PercentageLandAreaUnderForestCover}$

This is a straight forward question. We need to add the percentage of animals and divide it by summation of percentage of land area under forest cover.
Required population density $=\frac{20+15}{22+18}=0.88$
Hence, option (c) is the answer.