Question

If the position vector of a point (−4, −3) be $\overrightarrow{a,}$ find $\left|\overrightarrow{a}\right|$.

Answer 1

Given a point $\left(-4,-3\right)$ such that its position vector $\overrightarrow{a}$ is given by
$\overrightarrow{a}=-4\stackrel{\wedge }{i}-3\stackrel{\wedge }{j}$
Then,
$\left|\overrightarrow{a}\right|=\sqrt{{\left(-4\right)}^2+{\left(-3\right)}^2}=\sqrt{16+9}=\sqrt{25}=5$