If the position vectors of A,B,C,D are respectively (−6,1,6)(6,−2,3), (−2,−3,−1) and (−5,−9,−7), then
A
∠BCA is a right angle
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B
∠CDA is a right angle
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C
∠BDA is a right angle
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D
∠ACD is a right angle
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Solution
The correct option is D∠BCA is a right angle Looking at the given position vectors, we get ¯¯¯¯¯¯¯¯BC=−8¯i−1¯j−4¯¯¯k ¯¯¯¯¯¯¯¯AC=4¯i−4¯j−7¯¯¯k ¯¯¯¯¯¯¯¯¯CD=−3¯i−6¯j−6¯¯¯k ¯¯¯¯¯¯¯¯¯AD=1¯i−10¯j−13¯¯¯k ¯¯¯¯¯¯¯¯AB=12¯i−3¯j−3¯¯¯k ¯¯¯¯¯¯¯¯¯BD=−11¯i−7¯j−10¯¯¯k Thus, ¯¯¯¯¯¯¯¯AC.¯¯¯¯¯¯¯¯BC=0 and hence option A is correct.