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Question

If the position vectors of A, B, C, D are a,b.2a+3b,a2b respectively, then AC,DB,BA,DA are?

A
a+3b,3ba,ab,2b
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B
2b,b2a,3b+a,ba
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C
a3b,3ba,a+b,2b
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D
2b,b2a,3ba,ba
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Solution

The correct option is A a+3b,3ba,ab,2b
Given,

OA=a
OB=b
OC=2a+3b
OD=a2b
Then,
AC=OCOA=a+3b
DB=OBOD=3ba
BA=OAOB=ab
DA=OAOD=2b

Therefore,
AC,DB,BA and DA are a+3b,3ba,ab,2b respectively.


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