If the potential difference between the plates of a capacitor is increased by 20%, the energy stored in the capacitor increases by exactly

20%

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22%

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40%

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44%

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Solution

The correct option is D
44%

$U_{1} = \frac{1}{2} C V^{2}, U_{2} = \frac{1}{2} C (1.2 V)^{2} = \frac{1}{2} C V^{2} \times 1.44 ∴ \frac{U_{2} - U_{1}}{U_{1}} \times 100 = (1.44 - 1) \times 100 = 44$

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If the potential difference between the plates of a capacitor is increased by 20%, the energy stored in the capacitor increases by exactly

The correct option is D 44% U1=12CV2,U2=12C(1.2V)2=12CV2×1.44∴U2−U1U1×100=(1.44−1)×100=44

The correct option is D
44%

$U_{1} = \frac{1}{2} C V^{2}, U_{2} = \frac{1}{2} C (1.2 V)^{2} = \frac{1}{2} C V^{2} \times 1.44 ∴ \frac{U_{2} - U_{1}}{U_{1}} \times 100 = (1.44 - 1) \times 100 = 44$