If the power factor in a circuit is unity, then the impedance of the circuit is

Inductive

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Capacitive

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Partially inductive and partially capacitive

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Resistive

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Solution

The correct option is D Resistive
$cos ϕ = 1$
$\Rightarrow tan ϕ = 0$
$\Rightarrow ω L - \frac{1}{ω C} = 0$
$\Rightarrow | Z | = \sqrt{R^{2} + (ω L - \frac{1}{ω C})^{2}} = R$
Hence, the circuit is purely resistive.

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If the power factor in a circuit is unity, then the impedance of the circuit is

The correct option is D Resistivecosϕ=1⇒tanϕ=0⇒ωL−1ωC=0⇒|Z|=√R2+(ωL−1ωC)2=RHence, the circuit is purely resistive.

The correct option is D Resistive
$cos ϕ = 1$
$\Rightarrow tan ϕ = 0$
$\Rightarrow ω L - \frac{1}{ω C} = 0$
$\Rightarrow | Z | = \sqrt{R^{2} + (ω L - \frac{1}{ω C})^{2}} = R$
Hence, the circuit is purely resistive.