If the power of a lens is + 0.1 D and if the object of size 2 cm is placed 5 cm before the lens. Find the size and position of the image formed.
image size = 4 cm, image distance = – 10 cm
P = 1f ⇒ f = 10 cm
1v - 1u = 1f
1v - 1(−5) = 1(10)
v = - 10 cm
vu = h/h ⇒ −10(−5) = h/2
h/ = 4 cm
Image height = 4 cm