Question

If the power of a motor be $100$kW, at what speed can it raise a load of $50,000$N?

Answer 1

Load to be raised $F=50,000N$

Input power of the motor $P=100kW$

$\therefore P=100\times 1000W={10}^{5}W$

Let the speed by which the load is raised be $v$.

Using the relation $P=Fv$

$\therefore$ ${10}^5=50000\times v$

$⟹v=\frac{{10}^5}{50000}=2m/s$