If the pressure and absolute temperature of $2 L$ of carbon dioxide gas are double, the volume of the gas would become.

2 L

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4 L

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5 L

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7 L

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Solution

The correct option is A $2 L$
$\frac{P V}{T} = n R =$ constant
$∴ \frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$
$\frac{P \times 2 L}{T} = \frac{2 P \times V_{2}}{2 T}$
$V_{2} = 2 L$ .

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