If the pressure exerted on a gas is increased by 4 times and temperature is increased by 9 times, what will be the change in volume occupied by the gas?

\frac{5}{9}

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\frac{10}{9}

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\frac{5}{18}

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\frac{4}{9}

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Solution

The correct option is A $\frac{5}{9}$
According to ideal gas equation,
$P V = n R T$
$\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$
$P V / T = 4 P V_{2} / 9 T$
$V_{2} = 9 V / 4$

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If the pressure exerted on a gas is increased by 4 times and temperature is increased by 9 times, what will be the change in volume occupied by the gas?

The correct option is A 59According to ideal gas equation,PV=nRTP1V1T1=P2V2T2PV/T=4PV2/9TV2=9V/4

The correct option is A $\frac{5}{9}$
According to ideal gas equation,
$P V = n R T$
$\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$
$P V / T = 4 P V_{2} / 9 T$
$V_{2} = 9 V / 4$