Question

If the pressure of a gas at S.T.P is doubled and the temperature is raised to 546 K. What is the final Volume of the gas?

• A. Same
• B. Doubled
• C. Tripled
• D. Cannot tell

Answer 1

The correct option is

B

Same

By Gas Law -

$\frac{P_1{V}_1}{T_1}=\frac{P_2{V}_2}{T_2}$

$P_1=1atm$

$T_1=273K$

$V_1=22.4l$

$P_2=2\times 1=2atm$

$T_2=546K$

$\frac{1\times 22.4}{273}=\frac{2\times V_2}{546}$
$V_2=22.4l$

$\therefore V_2=V_1$