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Question

If the pressure of a gas contained in a closed vessel is increased by 0.4% when heated by 1 C, its initial temperature must be:

A
250 K
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B
250 C
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C
25 C
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D
25 K
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Solution

The correct option is A 250 K
Given information:
Initial pressure of the gas P1=P atm
Initial temperature of the gas T1=T K
Final temperature of the gas T2=(T+1) K
Final Pressure of the gas P2=P+0.004P atm
From Gay Lussac's law, P1T1=P2T2 at constant volume.


PT=1.004PT+1

1.004T=T+10.004T=1

T=250 K
Hence the intial temperature T1=250 K

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