If the pressure of a gas contained in a closed vessel is increased by 0.4% when heated by 1∘C, its initial temperature must be:
A
250K
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B
250∘C
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C
25∘C
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D
25K
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Solution
The correct option is A250K Given information:
Initial pressure of the gas P1=Patm
Initial temperature of the gas T1=TK
Final temperature of the gas T2=(T+1)K
Final Pressure of the gas P2=P+0.004Patm
From Gay Lussac's law, P1T1=P2T2 at constant volume.