Question

If the pressure of $N_2/H_2$ mixture in a closed vessel is $100$ atmosphere and $20\%$ of the mixture then reacts, the pressure at the same temperature would be:

• A. $100$ atm
• B. $110$ atm
• C. $90$ atm
• D. $80$ atm

Answer 1

The correct option is C $90$ atm

$\left(C\right)$ option is correct

As 4 moles react to form 2 moles of product.

Therefore, 20 atm pressure will react to just 10 atm pressure

$\therefore Pressure,P=100-20+10=90$ atm.