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Question

If the pressure of the gas contained in a closed vessel is increased by 30% when heated by 273 C then, calculate initial temperature?

A
1052 C
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B
1029 K
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C
910 C
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D
910 K
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Solution

The correct option is D 910 K
Given information:
Initial pressure of the gas P1=P atm
Initial temperature of the gas T1=T K
Final temperature of the gas T2=(T+273) K
Final Pressure of the gas P2=P+0.3P atm
From Gay Lussac's law, P1T1=P2T2 at constant volume.

PT=1.3PT+273

1.3T=T+2730.3T=273

T=910 K

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