If the probability for A to fail in an examination is 0.2 and that for B is 0.3, then the probability that either A or B fails is 0.5.
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Solution
Given, P(A fails in examination)=0.2 and P(B fails in examination)=0.3 P(A∩B)=P(A)P(B)=(0.2)(0.3)∴P(A∪B)=P(A)+P(B)−P(A∩B)=0.2+0.3−0.06=0.44 Hence, it is a false statement