If the probability of occurence of an event is p then the probability of non-happening of this event is [CBSE 2013C]

(a) (p − 1)
(b) (1 − p)
(c) p
(d) $(1 - \frac{1}{p})$

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Solution

P(occurence of an event) = p
P(non-occurence of this event) = 1 − p

Hence, the correct answer is option (b).

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If the probability of occurence of an event is p then the probability of non-happening of this event is [CBSE 2013C] (a) (p − 1) (b) (1 − p) (c) p (d) 1-1p

P(occurence of an event) = p P(non-occurence of this event) = 1 − p Hence, the correct answer is option (b).

If the probability of occurence of an event is p then the probability of non-happening of this event is [CBSE 2013C]

(a) (p − 1)
(b) (1 − p)
(c) p
(d) $(1 - \frac{1}{p})$

P(occurence of an event) = p
P(non-occurence of this event) = 1 − p

Hence, the correct answer is option (b).