If the probability of winning a game is 0.6, what is the probability of losing it?
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Solution
Let E be the event of winning a game.
Then, ( not E) is the event of not winning the game or of losing the game.
Then, P(E) = 0.6
Now, P(E) + P(not E) = 1
⇒0.6 + P(not E) = 1
⇒P(not E) = 1− 0.6 = 0.4
∴ P(losing the game) = P(not E) = 0.4