If the product of abscissa of point $A$ ( $10, - 5$ ) and ordinate of point $B$ ( $2, k)$ is $50$ . Then find the value of $k$ .
(2 Marks)

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Solution

Given,
Abscissa of point $A$ ( $10, - 5)$ is $10$ . (0.5 Marks)
Ordinate of point $B$ ( $2, k)$ is $k$ . (0.5 Marks)
ATQ,
Product of abscissa and ordinate = $50$
$10 \times k = 50$
$k = 5$ .......(1 Mark)
Therefore, value of $k$ is $5$ .

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If the product of abscissa of point A(10,−5) and ordinate of point B(2,k) is 50. Then find the value of k. (2 Marks)

Given, Abscissa of point A(10,−5) is 10. (0.5 Marks) Ordinate of point B(2,k) is k. (0.5 Marks) ATQ, Product of abscissa and ordinate = 50 10×k=50 k=5.......(1 Mark) Therefore, value of k is 5.

If the product of abscissa of point $A$ ( $10, - 5$ ) and ordinate of point $B$ ( $2, k)$ is $50$ . Then find the value of $k$ .
(2 Marks)

Given,
Abscissa of point $A$ ( $10, - 5)$ is $10$ . (0.5 Marks)
Ordinate of point $B$ ( $2, k)$ is $k$ . (0.5 Marks)
ATQ,
Product of abscissa and ordinate = $50$
$10 \times k = 50$
$k = 5$ .......(1 Mark)
Therefore, value of $k$ is $5$ .