Question

If the product of number of free electrons and number of holes in a silicon intrinsic semiconductor is ${10}^{36}$, then number of free electrons is -

• A. ${10}^{25}$
• B. ${10}^{30}$
• C. ${10}^{36}$
• D. ${10}^{18}$

Answer 1

The correct option is D ${10}^{18}$

We know that,

$n_e{n}_h=n_i^2$

$\Rightarrow n_i^2={10}^{36}$

$\Rightarrow n_i={10}^{18}$

Also, $n_e=n_h=n_i$

So, $n_e={10}^{18}$

Hence, option $\left(D\right)$ is the correct answer.