If the product of roots of the equation x2−3(2a+4)x+a2+18a+81=0 is unity, then a can take the values as
A
3, -6
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B
10, - 8
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C
-10, -8
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D
-10, -6
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Solution
The correct option is C -10, -8 The product of the roots is given by: a2+18a+811. Since product is unity we get: a2+18a+81=1 Thus, a2+18a+80=0 Solving, we get a = - 10 and a = - 8.