If the product of roots of the equation x2−3kx+2e2 loge k−1=0 is 7, then its roots will real when
None of these
Given equation can be written as
x2–3kx+2k2–1=0
So the product of roots is 2k2 – 1. But the product of roots is 7
Hence 2k2−1=7⇒2k2=8⇒k=±2
But k cannot be negative