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Question

If the product of the roots for the equation x2 – 3kx +2e2ln(k) -1=0 is 7, then the roots of the equation are real for k= ?

A
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B
2
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C
4
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Solution

The correct option is B 2

Answer = c

Product of roots = 2e2ln(k) -1 = 7; 2e2ln(k) = 8; e2ln(k) = 4; k2 = 4; k = ±2

For the roots to be real, k>0 k=2. to recheck CHECK for D>0; D= 9k2 -4 (2e2ln(k) -1) = 8>0


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