If the product of the roots for the equation x2 – 3kx +2e2ln(k) -1=0 is 7, then the roots of the equation are real for k= ?
Answer = c
Product of roots = 2e2ln(k) -1 = 7; 2e2ln(k) = 8; e2ln(k) = 4; k2 = 4; k = ±2
For the roots to be real, k>0 k=2. to recheck CHECK for D>0; D= 9k2 -4 (2e2ln(k) -1) = 8>0