Question

If the product of the roots of the equation is 6

$2x^2-(a+1)x+(a-1)=0$ then find the value of $a$.

Answer 1

We have,

$2x^2-(a+1)x+(a-1)=0$…… (1)

Product of roots $=6$

Then,

Comparing that,

$A{x}^2+Bx+C=0$

So,

$\text{Product}\text{of}\text{roots}=\frac{C}{A}$

Now,

$6=\frac{a-1}{2}$

$\Rightarrow a-1=12$

$\Rightarrow a=13$

Hence, this is the answer.