You visited us 1 times! Enjoying our articles? Unlock Full Access!

Roots of a Quadratic Equation

If the produc...

Question

If the product of the roots of the quadratic equation $m x^{2} - 2 x + (2 m - 1) = 0$ is $3$ , then the value of $m$ is

1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $- 1$
$m x^{2} - 2 x + (2 m - 1) = 0$
Product of the roots is
$3 = \frac{2 m - 1}{m}$
$\Rightarrow 3 m = 2 m - 1 \Rightarrow m = - 1$

Suggest Corrections

Similar questions

m x^{2} - 2 x + (2 m - 1) = 0

3

m

m x^{2} - n x + k = 0

tan 33^{o}

tan 12^{o}

\frac{2 m + n + k}{m}

α, β

m x^{2} + 6 x + (2 m - 1) = 0 \forall m \in R - {0, \frac{1}{2}},

\frac{1}{α}, \frac{1}{β}

3 : 1

2 x^{2} + 5 x + m = 0

m

m

50

m x^{2} + (2 m - 1) x + (m - 2) = 0

Join BYJU'S Learning Program

Explore more

Join BYJU'S Learning Program