Question

If the product of the zero's of the polynomial $(a{x}^2-6x-6)$ is $4$, find the value of a.

Answer 1

Let $\alpha$ and $\beta$ be the zero's of $(a{x}^2-6x-6)$.

Then, $\alpha \beta$ = $\frac{-6}{a}$ ......(i)
Since, given product is $\alpha \beta =4$.....(ii)
From equation (i) and (ii), we get
$\frac{-6}{a}=4$

$4a=-6$

$\therefore a=\frac{-3}{2}$