If the product of the zeros of the polynomial $(a x^{2} - 6 x - 6)$ is $4$ , find the value of $a$ .

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Solution

Let the Zeroes of polynomial
be $α, β$
So $α β = \frac{c}{a} = 4$
$a x^{2} - 6 x - 6$
$\frac{c}{a} = \frac{- 6}{a} = 4$
So a $= \frac{- 6}{4} = \frac{- 3}{2}$

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