Question

If the product of the zeros of the quadratic polynomial

$p\left(x\right)=(k-2)x^2-4x+k$, is 3, find the value of k.

Answer 1

$p\left(x\right)=(k-2)x^2-4x+k$

On comparing it to the general form, we have,

$a=k-2,b=-4,c=k$

Now, product of zeros $=\frac{c}{a}=\frac{k}{k-2}$

But it is given that product of zeros is 3.

Thus,

$\frac{k}{k-2}=3$

$k=3k-6$

$k=3$