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Question

If the product of three consecutive terms of G.P. is 216 and the sum of product of pair-wise is 156, then the numbers will be
[MNR 1978]

A

1, 3, 9

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B

2, 6, 18

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C
3, 9, 27
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D
2, 4, 8
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Solution

The correct option is B

2, 6, 18


Let numbers are ara,ar
Under conditions, we get ara.ar=216a=6
And sum of product pair wise = 156
ar.a+ar.ar+a.ar=156r=3
Hence numbers are 2, 6, 18.

Trick : Since 2×6×18=216 (as given) and no other option gives the value.


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