MyQuestionIcon

9

You visited us 9 times! Enjoying our articles? Unlock Full Access!

Number of Elements in a Cartesian Product

If the produc...

Question

If the product of two coprime numbers $x$ and $y$ is $36,$ then total number of ordered pairs $(x, y)$ is

Open in App

Solution

Factor of $36 = 1, 2, 3, 4, 6, 9, 12, 18, 36$
Possible pairs are
$(1, 36), (4, 9), (9, 4), (36, 1)$

Suggest Corrections

thumbs-up

1

Similar questions

Q. If the sum of two coprime numbers

x, y (x < y)

20,

then the total possible number of ordered pair(s)

(x, y)

Q. If three numbers

(x, y, z) = (\frac{2}{3}, \frac{7}{6}, \frac{8}{9})

108 (L.C.M. \times H.C.F.) = p \times q

p, q

are coprime to each other, then the total number of posiible pairs of

(p, q)

x, y \in [0, 2 π]

then the total number of ordered pairs

(x, y)

sin x \cdot cos y = 1

Q. If three coprime numbers

x, y, z

are such that the product of

x

y

551

y

z

1073,

x + y + z

x, y \in [0, 2 π]

, then total number of ordered pairs

(x, y)

satisfying the equation

sin x . cos y = 1

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Cartesian Product

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Number of Elements in a Cartesian Product

Standard XII Mathematics

Join BYJU'S Learning Program

CrossIcon