Question

If the product of two numbers is $4032$ and their H.C.F. is $12$ , find their L.C.M.

Answer 1

Finding the LCM :

We know that, $\mathrm{HCF}\times \mathrm{LCM}=\mathrm{Product}\mathrm{of}\mathrm{two}\mathrm{number}$

Therefore,

$\begin{array}{rcl}\mathrm{LCM}& =& \frac{\mathrm{Product}\mathrm{of}\mathrm{two}\mathrm{numbers}}{\mathrm{HCF}}\\ & =& \frac{4032}{12}\\ & =& 336\end{array}$

Hence , the L.C.M of two numbers is $336$.