If the product of two roots of $x^{3} + 3 x^{2} - 10 x + k = 0$ is $8$ , then $k =$

- 10

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24

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- 24

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10

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Solution

The correct option is B $- 24$
$a, b, c a r e t h e r o o t s a b = 8, a + b + c = - 3 \sum a b = - 10 W e g e t c = 3 a b c = - k T h e r e f o r e, k = - 24$

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